RE: PWM Polarity Inverting Circuit for TEC module using DRV8432 in parallel...
Hi Rick, Thanks for the prompt reply. I am switching the direction pin from logic high to low and low to high for heating and cooling using a logical switch. I am just sending a switch output for...
View ArticleRE: current sensing low pass filtering , DRV8302
Hi Mark, In general, using a LPF in software is a good idea. If you do so, it is recommended to also use the overcurrent detection through the OC_ADJ input. This will respond to abnormal conditions....
View Articlecurrent sensing low pass filtering , DRV8302
hi!I have been using BOOSTXL-DRV8301 for BLDC motor control.in the circuit schematic i saw that the current feedback (after the differential OPA stage) is fed into RC low pass filter and after the...
View ArticleRE: Ringing on output of DRV8432
I found this post that may be of benefit: e2e.ti.com/.../403063
View ArticleRinging on output of DRV8432
Hello, I am using the DRV8432 in my design, and I am getting a lot of ringing on the output at the solenoids, and motors that I am controlling. I have followed the recommended design that was given by...
View ArticleRE: PWM Polarity Inverting Circuit for TEC module using DRV8432 in parallel...
Hi Sai, Are you monitoring VDD with a scope or a DMM? It is important to use a scope and use the nFAULT and nOTW signals to capture the details of the event. Looking at the outputs with respect to the...
View ArticlePWM Polarity Inverting Circuit for TEC module using DRV8432 in parallel full...
Hello,I am working on a PWM polarity inverting circuit for TEC module with 24V power supply, 1 TEC requires 12A driving current in total. so I am using DRV8432 in Parallel full bridge mode with my...
View ArticleRE: DRV10983 - StepDown Regulator to Linear Regulator
Dear TI-er.How to decided the resistor value & watt ?I want to know the resistor's range.plz help me.
View ArticleDRV10983 - StepDown Regulator to Linear Regulator
Dear TI-er.My customer is designed using DRV10983.Internal StepDown Regulator is designed Linear regulator.V3P3(Pin 9) is used Pullup resistor's power source of I2C, FG .But, SW(Pin 4) resistor may be...
View ArticleRE: DRV8871 startup
Hello Rick-san,Thank you for your detailed comment.The customer have tired 23k Ohm resistor and any abnormal waveform was not observed. And they have tried with 15k Ohm again, there was no abnormal...
View ArticleRE: DRV8871 startup
Hi Sato-san, The datasheet describes the minimum resistance is 15k Ohm, but do the current regulation operate unstable with 15k Ohm in their application ?>> At 15k, the current regulation is...
View ArticleDRV8871 startup
Hello,Our customer now trying to use DRV8871, but their startup current is too big(about 5A/1us) and the device could not operate correctly.It seems that it due to current regulation (not OCP), so they...
View ArticleRE: DRV110 PWM Signal - FET not coming fully on every time
Hi Jordan, Our experts have been contacted and should reply soon.
View ArticleRE: DRV110 PWM Signal - FET not coming fully on every time
Hi Jordan,Sorry, but the images did not come through. Please select "Use rich formatting" and try again. You may have to save the image as a file and select either insert/edit media or insert file.
View ArticleRE: DRV110 Output Signal Problem
Hi Jordan, Since this is a duplicate of POST e2e.ti.com/.../535482 , I would like to close it. Do you have any objections?
View ArticleRE: DRV110 Output Signal Problem
The other one wasn't showing up so that is why I posted it. It appears the old one is showing up now, so that is fine.
View ArticleRE: DRV110 Output Signal Problem
Hi Jordan, Thanks. Depending of the size of the images, it can take 30 minutes to an hour to load.
View ArticleDRV110 Output Signal Problem
A solenoid driver has been designed using the DRV110 APWR. It is designed to handle a pick current of 10A and a hold current of 0.6A. It is oscillating at 20 kHz and offers a 1s keep time for the pick...
View ArticleRE: Abnormal Kt detect with DRV10983
Hi Howard,The integration or area under curve for a*sin(w*f*t) is equal to a/(pi*f) where f is frequency, a is amplitude, w is 2*pi. So basically we are dividing amplitude by frequency to get back emf...
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